4x^2-600x+18000=0

Solution for 4x^2-600x+18000=0 equation:

4x^2-600x+18000=0

a = 4; b = -600; c = +18000;
Δ = b2-4ac
Δ = -6002-4·4·18000
Δ = 72000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{72000}=\sqrt{14400*5}=\sqrt{14400}*\sqrt{5}=120\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-600)-120\sqrt{5}}{2*4}=\frac{600-120\sqrt{5}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-600)+120\sqrt{5}}{2*4}=\frac{600+120\sqrt{5}}{8}
$